On my homework, this is the only problem with a number outside the parenthesis. I am looking through my notes and the book and it doesn't say how to solve it.
FYI, ^2 and ^3 is to the second power and to the third power if you didn't know. So that would be (14x+3-41x squared +x cubed)
This goes under adding and subtracting polynomials.
2007-02-05 16:02:19 · 5 answers · asked by Onions 2 in Science & Mathematics ➔ Mathematics
Since you are just adding a subtracting, the parenthesis don't mean anything...you can disregard them and solve it like the others
2007-02-05 16:09:54 · answer #1 · answered by robdog9151 2 · 0⤊ 0⤋
since you're adding and there is no multiple outside of the brackets, you can just disregard them.
this is the same as 8x + 14x + 3 - 41x^2 + x^3
= x^3 - 41x^2 + 22x + 3
2007-02-05 16:08:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋
no longer adequate options to sparkling up for x, yet you could component: 8x^2 - 14x + 3 = 8x^2 - 12x - 2x + 3 = 4x(2x - 3) - (2x - 3) = (4x - a million)(2x - 3) If 8x^2 - 14x + 3 = 0, then: 4x - a million = 0 or 2x - 3 = 0 4x = a million or 2x = 3 x = a million/4 or x = 3/2 x = 0.25 or x = a million.5
2016-11-02 11:01:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You did solve it because you combined the like terms in your question.
(14x+3-41x squared +x cubed)
2007-02-05 16:10:37 · answer #4 · answered by csucdartgirl 7 · 0⤊ 0⤋
Add like terms together:
22X+3 - 41X^2 +X^3
Generally we put the highest order ( biggest exponent ) term first:
x^3 - 41x^2 + 22x + 3
2007-02-05 16:08:01 · answer #5 · answered by John T 6 · 0⤊ 0⤋