If g(x) = 9 + x + 9e^(x-6), find g^(-1) (24)?

Answer 1

g(x)=9+x+9e^(x-6)
x=9+g^(-1)(x)+9e^(g^(-1)(x)-6)
To find g^(-1)(24)

24=9+g^(-1)(24)
+9e^(g^(-1)(24)-6)

15=g^(-1)(24)
+9e^(g^(-1)(24)-6)

g^(-1)(24)
+9e^(g^(-1)(24)-6)-15=0

Try and error
we get g^(-1)(24)=6

g^(-1)(24)
+9e^(g^(-1)(24)-6)-15
=6+9e^(6-6)-15
=6+9e^0-15
=6+9-15
=0

Answer 2

G^(-1)(24) MEANS FIND X WHEN G(X)=24

SO
24 = 9+X+9e^(X-6)
15 = X+9e^(X-6)
THIS IS TRUE WHEN X=6 BECAUSE
15=6+9e^(6-6) OR 15= 6+9e^0 OR 15= 6+9

SO X=6