2007-02-05 15:05:21 · 8 answers · asked by Jerome C 1 in Science & Mathematics ➔ Mathematics
Let's let the number be x and look like: abc (i.e., a is the first digit, b the second, c the third).
Since the sum of the digits is 4, c can only be 3, 2, 1, or 0. It can't be 2 or 0 though, because then x would be divisible by 2. And it can't be 3, because then x must be 103, which is not divisible by 7. So c=1.
Now we're left with only three options: 121, 211, or 301 (if a was 0, then this wouldn't really be a three-digit number). If you check these three possibilities, you'll find that 301 is the only option that is divisible by 7 (301/7=43). So x=301.
(This is all assuming that we're working in base 10 with the usual digits of 0-9...if you give some wiggle room on the base, we could conceivably come up with other answers...)
2007-02-05 15:19:13 · answer #1 · answered by Ben 6 · 0⤊ 0⤋
Use logic to figure it out.
The sum of the digits is 4, so none of the numbers can be greater than 4. The ones digit can't be an even number or it will be divisible by 2.
301
211
103
121
are the possible choices. Of these, only 301 is divisible by 7. 301/7=43.
2007-02-05 23:10:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
301
2007-02-05 23:56:43 · answer #3 · answered by sri hari madhav k 1 · 0⤊ 0⤋
301
2007-02-05 23:22:07 · answer #4 · answered by Gama 1 · 0⤊ 0⤋
301
2007-02-05 23:19:36 · answer #5 · answered by livin.dream 2 · 0⤊ 0⤋
301
2007-02-05 23:09:37 · answer #6 · answered by fade_this_rally 7 · 0⤊ 0⤋
The answer is 301
2007-02-05 23:16:13 · answer #7 · answered by pasunman 1 · 0⤊ 0⤋
301?
2007-02-05 23:11:57 · answer #8 · answered by krayziexmami 2 · 0⤊ 0⤋