2 runners approahing each other on a straight track have constant speeds of 4.50m/s and 3.50m/s, respectively, when they are 100m apart. How long will it take for the runners to meet, and at what position will they meet if they maintain these speeds?
2007-02-05 14:54:19 · 4 answers · asked by Morena 1 in Science & Mathematics ➔ Physics
You can figure this out like this:
In 1 second:
4.5m+3.5m=8m
If the whole track is 100 m long, divide 100 m over 8 to get the time, in seconds.
Time = 12.5 seconds
Multiply any of them by 12.5:
For the 4.5m/s runner:
4.5*12.5=56.25 m from his starting point
For the 3.5m/s runner:
3.5*12.5=43.75 m from his starting point
2007-02-05 15:03:55 · answer #1 · answered by F B 3 · 0⤊ 0⤋
If 12.5 seconds is right then because the 4.5m\s runner is faster they will meet at the 56.25 metre mark
2007-02-05 23:10:04 · answer #2 · answered by visyboy 3 · 0⤊ 0⤋
They'll meet at Starbucks.
2007-02-05 23:04:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
they will meet in 12.5 seconds.
I don't have time to figure the rest out now
2007-02-05 22:58:26 · answer #4 · answered by Myglassesarealwaysclean 5 · 0⤊ 0⤋