can someone answer this please..?

Question

The length of one side of a square is decreased by 2 meters and the lenght of an adjacent side is increasedby 1 meter. In the resulting rectangle, the lengthis twice the width. How long was a side of the original square?

Answer 1

x - 2 = n
x + 1 = 2n

solve the system to find x - the side of original square

multiply first equation by -2 and add to the second one and you'll get

-x + 5 = 0

x = 5 meters

Answer 2

Alright, so originally you have a square with 4 sides, and a rectangle with 4 sides. Knowing what we know about squares and rectangles we can assign these sides variables (any letter you want, I prefer x,y, and z).
All four sides of the square are equal to x.
This rectangle has four sides, two are equal to y, and the other two are equal to z.
We know that one side is decreased by 2 meters: z = x -2; one side is increased by one meter: y = x + 1; and one side is twice the length of the other: y = 2z.
So, we need to find x:
z = x - 2
y = 2z
y = x + 1
We substitute:
x + 1 = 2z, and z = x - 2
So we substitute a little more:
x + 1 = 2(x - 2)
Then we multiply
x + 1 = 2x - 4
Then we move like terms to the same side:
4+1 = 2x-x
Thus,
x = 5 meters

Answer 3

the original sides of a squre would be 4m

4+2=6
4-1=3

L=2W
6=2(3)

Answer 4

x+2=2(x-1)
x+2=2x-2
4=x=the original length.