4y+4x=0
-y-2=X Solve the elimination
2007-02-05 14:26:32 · 6 answers · asked by cncdataentry 1 in Science & Mathematics ➔ Mathematics
i agree wit da psycho dude...thats the riight answer
2007-02-05 14:30:35 · answer #1 · answered by Shy 2 · 1⤊ 0⤋
4y + 4x = 0
Given -y -- 2 = x
Substiute x in equation (1) with -y--2 since x equals to it.
Then,
4y + 4(--y--2) = 0
4y --4y --8 = 0 (distribute)
0--8=0
Since --8 is not equal to 0, in mathematics, this implies that the answer is indeterminate, that is, there are many and almost infinite number of solutions or no solution for all.
I suppose that with --y--2 as a condition, it does not have a solution.
If we do, however, another solution:
4x + 4y = 0
-y - 2 = x
We rearrange the bottom:
4x + 4y = 0
-x - y = -2
After that, we find a common number to subtract. We will use x. Simply, we multiply by 4:
4x + 4y = 0
-4x - 4y = -8
We add them, thus: you will notice that:
0 = --8
Hence, I confirm that the answer is INDETERMINATE.
2007-02-05 22:34:49 · answer #2 · answered by Mig 2 · 1⤊ 1⤋
4x+4y=0
-x-y=2
4x+4y=0
-4x-4y=2
=======
0x+0y=2
No Solution!
2007-02-05 23:22:33 · answer #3 · answered by Anonymous · 0⤊ 1⤋
4y+4x=0
-y-2=X
one easy way to do this is to multiply the second equation by 4, then subract the first from the second equation
4y+4x=0
-4y-8=4X
so 4x - 8 = -4x
8x=8
x=1
Now substitute in first equation
4y + 4(1) = 0
y = -1
2007-02-05 22:32:18 · answer #4 · answered by ignoramus 7 · 0⤊ 3⤋
4y+4x=0
4y+4(-y-2)=0
4y-4y-8=0
-8=0
No solution.
2007-02-05 22:29:01 · answer #5 · answered by PsychoCola 3 · 2⤊ 0⤋
eww i just got done with that lesson i hated it i dont really get algebra i didnt that lesson
im just barley passing that class ive got a 70%
lol
sorry
hey are you in 8th or 9th im in 8th
2007-02-05 22:31:21 · answer #6 · answered by Anonymous · 1⤊ 0⤋