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A model airplane whose mass is 0.864 kg is tethered by a wire so that it flies in a circle with radius 24 m. The airplane engine provides a net thrust of 0.742 N perpendicular to the tethering wire.

a) Find the torque the net thrust produces about the center of the circle.

b) Find the angular acceleration of the airplane when it is in level flight.

c) Find the linear acceleration of the airplane tangent to its flight path

2007-02-05 14:23:24 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

(a)T=rxFt
T=24 x 0.742 = 17.808

b) Tangential acceleration
at=Ft/m
angulal acceleration = at/r
angulal acceleration =Ft/(m r)
angulal acceleration = .742 /(0.864 x24 )
angulal acceleration = 0.036 rad/sec
c)at=Ft/m=0.859 m/s

2007-02-08 09:27:17 · answer #1 · answered by Edward 7 · 0 0

The torque is
.742*24 N m

the angular acceleration is related to the tangential by
v=r dth/dt where dth is the angular acceleration

since the force is tangential,
the angular acceleration is
.742/(.864*24)

and the tangential is
.742/.864

j

2007-02-08 09:31:02 · answer #2 · answered by odu83 7 · 0 0

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