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Length of a side

step by step pleaze

2007-02-05 14:06:09 · 3 answers · asked by boyz_inblu3 1 in Science & Mathematics Mathematics

length of the side,

seriously need help

the sum of the square of 2 consecutive odd positive intergers is 130.

2007-02-05 14:15:09 · update #1

3 answers

ok. the perimeter of a square is 4 * s
the area of the square is s^2
(s = length of side)

so, the if the inches in the perimeter is 3 more than the square inches in it's area

4s= s^2 + 3

now subtract 4s

s^2 -4s + 3 = 0

factor

(s - 3) (s - 1) = 0

s-1=0 or s-3=0

s=1 or s= 3

2007-02-05 14:11:23 · answer #1 · answered by Ace 4 · 1 0

assumption : x is the side length of that square,

so :

perimeter is 4x
area is x^2

perimeter of a square is 3 more than the # of square inches in its area
it means:
4x = x^2 + 3
0 = x^2 - 4x + 3
factorize :
0 = (x-3) (x-1)

first solution :
x-3 = 0
x = 3

second solution :
x-1 = 0
x = 1

so the length of sides could be 1 inch or 3 inches.

2007-02-05 22:14:38 · answer #2 · answered by Steve 1 · 0 0

let S=LENGTH OF A SIDE

PERIMETER=4*S
AREA=S*S

4*S=S*S+3

REGROUPING:
S*S-4*S+3=0

SOLVE FOR S USING QUADRATIC FORMULA:
S=1 OR S=3.

CHECK IT! IT WORKS!

2007-02-05 22:14:04 · answer #3 · answered by Hk 4 · 0 0

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