Can you give the angles and side lengths that make a triangle that's a counterexample to SSA congruence theorm

Question

please help. I already have an instance but I need a counterexample.

Answer 1

SSA is not a theorem (unless it's a right triangle) because at times two different triangles can exist with two matching sides and a not-included matching angle.

For example, one side = 10, one side = 9, and the angle at the end of the 10 that doesn't meet the 9 is 30 degrees. There would be two triangles possible: one with a 34 and a 116, and one with a 146 and a 4 in addition to the given 30.

Answer 2

Construct a circle with center A.
Construct a point B on the circle.
Construct a point C in the exterior of the circle.
Construct triangle ABC.
Construct Point D at the intersection of the circle and segment BC.
Construct segment AD

AB is congruent to AD (they are radii of the same circle)
AC is congruent to AC (Reflexive property)
Angle B is congruent to angle B (Reflexive property, again)

Triangle ABC is not congruent to triangle ABD,