Math Help!?

Question

Questions 1: Each side of a square is lengthened by 3 inches. The area of this new, larger square is 196 square inches. Find the length of a side of the original square.

Question 2: A machine produces open boxes using square sheets of metal. The machine cuts equal-sized squares measuring 3 inches on a side from the corners and the shapes the metal into an open box by turning up the sides. If each box must have a volume of 48 cubic inches, find the length and width of the open box.

Question 3: 6/2x^2-12x+12

Any of the answers will be fine and very much appreciated I am having trouble as I have solved it and it marks it as wrong answers...Please tell me how to solve!

Question 3: List all numbers that must be excluded from the domain of the rational expression. Write your answer as an exact answer, i.e. in radical form.

6 / 2x^2-12x+12

I need to find the two zeros, my answer was: 6/12+ or - squareroot(48)/4

I dont know how to simplify that I need help with that?

Answer 1

Question 1: x = side of original square
(x+3) * (x+3) = 196
x+3 = (square root)196
x+3 = 14
x=11 <---that's the answer.

Question 2: if each side of this square is 3 inches then each side is cut into three pieces and two of hte sides are thrown away.
SO a length/width of the cube is 3/3 which equals 1.

Question 3: 6/2x^2 = 3/x^2 (if the problem is written so that x squared is in the denominator)
I'm assuming the equation is equal to zero.
so it equals 1/x^2 -4x+4 = 0
1 = (4x-4)x^2
1/4 = (x-1)x^2
0 = 4x^3 -4x^2 - 1
use a calculator to solve it (graph and look for zeroes)


hope this helps!

Answer 2

take the sides of the original square as x. since its a square the x can apply for both length and width. so if each side is increased by 3 and the bigger square will be 196 cm squared then ur equation will look like this: (x+3)^2=196. so if we squareroot both sides of the equation then x+3=14. so therefore x=11. so the sides of the original square will be 11. i can only help u in question 1.

Answer 3

1. let x = the length of the original side
let y = x+3 = the new side

therefore, area = length x width = 2y

2y = 196
2(x+3) = 196
2(x+3) / 2 = (196)/2
(x+3) = 98
x+3-3 = 98 -3
x = 95

The length of the side of the original square is 95 inches.

(Not sure if this is correct, but here is a suggestion!)

Answer 4

1. square root of 196 = 14-3=11 is the answer
sorry didn't quite understand the last two questions.

Answer 5

do the sq.root. of 169 and u get 14

then do 14-3=11 so the length of a side on the original square is 11.

Answer 6

height of box = 3'
therefor base area = 48/3 =16'
box made of sq sheet, therefore box has sq base
length = width = root 16 = 4'

Answer 7

14x14=196
so the smaller square must be 11 x 11.

Sorry, but I don't understand question number 2.

Answer 8

(x+3) ^ 2 = 196
(x+3)(x+3) = 196

****************************** u work it from here
q2. x times x times 3 = 48
x squared = 16

******************************* u werk it from hear

q3. ?