Alg 2 (factoring)?

Question

I need help with these combined factoring problems:

1. a^3 +16a^2 + 64a

2. w^5 - 10w^4 + 25 w^3

3. 5a^2 + 10ab - 40b^2

4. -3xy^6 + 3xy^2

Thanks for the help!!!

Answer 1

The first one is

a(a² + 16a + 64) = a(a + 8)²

Now buckle down and get busy on the rest of them. Learning to factor is like learning to shoot hoops. You won't get better by watching Shaq sink 'em from half-court. And you won't get better at factoring by watching an old mathematician do them, Ya gotta practice it yourself if you want to get good at it ☺


Doug

Answer 2

1. a^3 +16a² + 64a = a(a² +16a + 64) = a(a + 8)²

2. w^5 - 10w^4 + 25w^3 = w^3(w² - 10w + 25) = w^3(w-5)²

3. 5a² + 10ab - 40b² = 5(a² + 2ab - 8b²) = (a+4b)(a-2b)

4. -3xy^6 + 3xy² = 3xy²(-y^4 + 1) = 3xy²(1-y^4)
= 3xy²(1-y²)(1+y²) = 3xy²(1-y)(1+y)(1+y²)

Answer 3

1. a^3 +16a^2 + 64a
a(a+8)(a+8)

2. w^5 - 10w^4 + 25 w^3
w^3(w-5)(w-5)

Answer 4

for the first one the ans is
a(a^2+16a+64)
a(a+8)^2

second ans
w^3(w^2+10w+25)
w^3(w+5)^2

third ans
5(a^2+2ab-8b^2)
5(a+4b)(a-2b)

fourth ans
3xy^2(-xy^4+xy)

these are ans if u need more help let me know i will help u out

Answer 5

1. a(a^2+16a+64)
a(a+8)^2
a(a+8)(a+8)

etc...the rest are all similar..factor out common factors

Answer 6

1. a(a+8)(a_8)
2. w^3 (w-5)(w+5)
3. 5 (a-2)(a+4)
4. 3xy^2 (1-y)(1+y)(1+y^2)

Answer 7

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