i need help with algebra please?

Question

i dont get it please help
solve by elimanation
5x - 3y - 2=0
-4x+ 3y - 2 =0

show me the steps to

um i not falling i got a B in math and i do pay attention in class its just we got this new teacher and he makes everything so confusing and he hardely teaches us so dont be so rude i just wanted help not the answer

an for our homewrk we have no directions

Answer 1

PROBLEM ABOVE IS WRONG. X AND Y DO NOT = 1

5x-3y=2
-4x+3y=2


20x-12y=8
-20x+15y=10
--------------------
3y=18

y=6

then plug back in->
5x-3(6)=2
5x=20
x=4

so x=4 and y=6

Answer 2

OK..first bring the -2 to the other side of the equal sign.
5x - 3y = 2
-4x + 3y = 2
Now you have a positive and a negative 3y which equals zero.
5x - 4x equals x and 2 + 2 =4 so x = 4.
Substitute the 4 for x and you get y = 6.
To check, substitute the values for x and y in each equation and it should work. Good luck....

Answer 3

Okay, first off you need to eliminate one of the variable by add/sub method. The Ys are already eliminated (-3+3=0) therefore, subract the Xs.

So,
x-4=0
and therefore x is 4

then plug in 4 for x in one of the equations to get y=6

5(4)-3y-2=0 so y=6


If your like me and you hate doing all that work and hate making a mistake buy a Ti-89 or go to www.quickmath.com. With this you can easily solve problems with Variables !!!! and elimination too. But dont let dont be a substitute for Learning how to do it.

Answer 4

in this case we have the same numerical value in front of the Y
but the signs are different so if we add the 2 equations together we will eliminate Y

5x - 3y - 2=0
-4x+ 3y - 2 =0
-------------------
5x-4x-3y+3y-2-2=0
simplify this and you get

x-4=0

or x=4

then sub that in to either of the equations above and you get

5(4)-3y-2=0
20-3y-2=0
-3y=-18
y=6

so your answer is (4,6)

and we can confirm this bu substituting those values in to the second equation

-4(4)+3(6)-2
=-16+18-2
=0

Answer 5

Elimanation, also known as addition, is a method of solving two equations by adding up the comparable parts. This equation is easy, because there are already inverse coefficients on y (3 and -3) They cancel each other, and eliminate the y. Then, add the two negative 2s (-4), 0s, and 4x and 5x. Then, with the y gone, you can solve for x, and use that value to solve for y in the original problem.

Answer 6

5x - 3y - 2=0
-4x+ 3y - 2 =0

add everything together...the 3's cancel out. 5+-4=1. so you're left with 1x-4=0. to get each variable for this system first you add four to -4 to cancel it out. and add 4 to 0 so it'll look like 1x=4. sooo x=4. to solve for y you put 4 back into one of your original equations...for example 5(4)-3y-2=0. y should be 6. so the ordered pair will look like this (4,6)

Answer 7

x = 4 , and y = 6

Answer 8

ok first you solve for one of the variables in either of the equations

lets pick the first on
solve for x
5x=2+ 3y
x= (2+3y)/(5)

so now you know what x is in terms of y

then you plug that into the second equation

-4(2+3y)/5) + 3y - 2 = 0
distribute the -4
(-8 - 12y) / (5) = 2 - 3y
then multiply the other side by five to make it easier
-8 - 12y = 10 -30y
solve for y
30y-12y = 10+8
18y= 18
y = 1

so now you have y

now refer back to the first equation
substitute the y
5x- (3)(1) -2 =0
5x-5=0
x=1

so x =1 and y =1

Answer 9

you could solve in two different ways, you could write one equation for x and plug it in the other formula or you could do the following:
add up the two formulas, you can see that the y gets canceled. Then solve for the x. and then when you have the number for it plug it in any one of the formulas and you will get y.
but in a case that nothing gets canceled when you add up just multiply both of the formulas by the other formulas x or y multiplier and then add up. this way one of ur unknowns will be canceled.

Answer 10

5x-3y-2=0
-4x+3y-2=0, 3y=4x+2,
5x-(4x+2)-2=0,
5x-4x-2-2=0,x=4
3y=4(4)+2,y=6.
so the ans is (4,6)