x+2/x+3 + 1/x²+2x-3-1+0
show your work
2007-02-05 12:52:44 · 4 answers · asked by sexyjay1962 1 in Science & Mathematics ➔ Mathematics
x+2/x+3 + 1/x²+2x-3-1=0
show your work
2007-02-05 12:54:36 · update #1
x+2/x+3 + 1/x²+2x-3-1=0
(x+2)/(x+3) + 1/(x^2+2x -3) -1= 0
(x+2)/(x+3) + 1/(x+3)(x-1) = 1
(x+2)(x-1) + 1 = (x+3)(x-1)
x^2+ x - 2 + 1 = x^2 + 2x - 3
x^2+ x - 2 + 1 - x^2 - 2x + 3 = 0
-x +2 = 0
x = 2
2007-02-05 13:03:37 · answer #1 · answered by Brian F 4 · 0⤊ 0⤋
Multiply through by x^2:
x^3 + 2x + 3x^2 + 1 + 2x^3 - 3x^2 - x^2
= 3x^3 - 2x^2 + 2x + 1
2007-02-05 20:59:17 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋
It depends on where you put your brackets. Here's my answer:
(x + 2)/(x + 3) + 1/(x² + 2x - 3) - 1= 0
(x + 2)/(x + 3) + 1/(x + 3)(x - 1) - 1= 0
x + 2 + 1/(x - 1) - (x + 3) = 0
x + 2 - x - 3 + 1/(x - 1) = 0
-1 +1/(x - 1) = 0
-(x - 1) + 1 = 0
-x + 2 = 0
x = 2
2007-02-05 20:57:42 · answer #3 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
you know u should learn this on your own, or you will fail the test with this material on it
2007-02-05 20:55:50 · answer #4 · answered by tennisfreak 1 · 0⤊ 1⤋