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How many moles of sulfate ions, cobalt(III) ions, and oxygen atoms are present in 0.408 mol of cobalt(III) sulfate?
Please Explain!

2007-02-05 12:51:55 · 1 answers · asked by just_curious 1 in Science & Mathematics ➔ Chemistry

1 answers

Cobalt (III) sulfate = Co2(SO4)3

0.408 mol Co2(SO4)3 contains:
(0.408)(2 Co) = 0.816 mol Co 3+ ions
(0.408)(3 SO4) = 1.224 mol SO4 2- ions
(0.408)([3 SO4] x 4 oxygen per SO4) = 4.896 mol O atoms

2007-02-05 13:10:49 · answer #1 · answered by physandchemteach 7 · 0⤊ 0⤋