d=r*t
d=(a+40)(3) with tail wind
d=(a-40)(8) against the wind
3a+120=8a-320
440=5a
a=88 km/hr
2007-02-05 12:52:00
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answer #1
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answered by Professor Maddie 4
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A flying boat?
Distance = rate x time
d = rt
Trip out: d = rt = (v0 + 40)(3) = 3v0 + 120
Trip back: d = rt = (v0 - 40)(8) = 8v0 - 320
Since d=d, the two above are equal and knowing that v0 is the time in still air:
3v0+120 = 8v0-320
5v0 = 320+120 = 440
v0 = 440/5 = 88 km/h
2007-02-05 12:55:08
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answer #2
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answered by kellenraid 6
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There is not enough information.
The first statement is referring to a fishing boat, then the second is attempting to find the speed of the airplane. You know nothing of this airplane.
2007-02-05 12:50:00
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answer #3
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answered by China 2
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Is this "fishing boat" flying through the water? Flying through the air?
How are your grades in English?
2007-02-05 12:52:06
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answer #4
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answered by dilettante 1
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If the scholars modern-day grade is a ninety% then we’re of direction assuming it’s out of a hundred% ninety/a hundred Now by using fact the scholars grade greater 20% from the final grading era then you definately upload that to the previous a hundred% supplying you with ninety/ one hundred twenty = .75 and because grades are in probabilities you multiply .75 by potential of a hundred supplying you with 75% by using fact the scholars previous grade
2016-12-17 03:20:31
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answer #5
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answered by lacy 4
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one trip is a fishing boat - the other is an airplane
so find the speed of the joggers?
2007-02-05 12:49:35
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answer #6
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answered by tom4bucs 7
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(x + 40) * 3 = (x - 40) * 8
3x + 120 = 8x - 320
440 = 5x
x = 88 km/hr
2007-02-05 12:51:10
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answer #7
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answered by thetunak 4
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ok are we talking about a boat or a plane? theres a HUGE difference between the two.
2007-02-05 12:50:32
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answer #8
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answered by kute_regina_gal 4
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the taxi was going at 88km/h
2007-02-05 12:59:01
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answer #9
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answered by christo 1
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