Simplify (2e-2f)(2f+8)=?

Question

A.4ef-4f^2
B.4ef+16e+4f^2+16f
C.4ef+16e-4f^2-16f
D.4ef-16e-4f^2-16f

Answer 1

The answer is C.

Use the FOIL method. First, Inside, Outside, Last.

First: 2e times 2f becomes 4ef
Outside 2e times 8 becomes 16e
Inside -2f times 2f becomes -4f^2
Last -2f times 8 becomes -16

So, 4ef-16e-4f^2-16f is the answer.

Answer 2

4ef+16e-16f-4f^2 C

Answer 3

c. 4ef+16e-4f^2-16f

2e x2f=4ef
-2f x 2f= -4f^2
2e x8= 16e
-2f x8 = -16f

Answer 4

use the FOIL rule for this one (First, Outside, Inside, Last)

(2e-2f)(2f+8)
=2e*2e -2f*2f+2e*8 -2f*8
=4e^2-4f^2+16e-16f
=4(e^2-f^2+4e-4f)

So C is your answer

Answer 5

c
(2e)(2f)-(2f)^2+(2e)8-(2f)8
4ef-4f^2+16e-16f