What is the slope if the secant line of the function y = 4x2 – 2x + 1 between x = 3 and x = 6?

Question

please explain steps also thanks

Answer 1

you want the slope OF the secant line? or the slope of the function IF the secant line is that function?
your first step is to plug in the x values into the original function.
then use those x and y values and just use the slope formula
[(y)-(y)]/ [(x)-(x)]
just remember to match the y value above its own x value.

Answer 2

I'm guessing you mean slope 'of' the secant. OK
At x = 3 then
y = 4*3²-2*3+1 = 31 so put a point at (3,31). Then, at
x = 6
y = 4*6²-2*6+1 = 133 so put a point at (6,133)
Now connect a straight line between these two points, that's the secant. The slope of *any* line between two points (x1,y1) and (x2,y2) is given by
m = (y2 - y1)/(x2 - x1) (also called 'rise over run') so, in this problem
m = (133 - 31)/(6 - 3) = 34.

Hope that helps.


Doug

Answer 3

remember that slope is rise/run, and the secant line just passes through the two points on the graph

evaluate y at x = 3 and x = 6: 31 and 133 respectively

plug in: (133 - 31)/(6-3) = 102/3 = 34

Answer 4

first solve for y then graph, remember formula for slope is rise over run.