dr/ds if r= s^3/2 +1
ANybody know how to do this problem, thanks.
2007-02-05 12:27:29 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Simple application of power rule:
r = s^(3/2) + 1
dr/ds = (3/2) s^(3/2 - 1) + 0
= (3/2) s^(1/2).
2007-02-05 12:31:35 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
Well, the rule is that the derivative of x^n is nx^(n-1)
So for your example, dr/ds = (3/2)s^1/2
2007-02-05 20:32:27 · answer #2 · answered by John D 3 · 0⤊ 0⤋
just basic derivative stuff, since ds is on the bottom you're differentiating in respect to s
use the power rule where d(x^n)/dx = n * x^(n-1)
dr / ds = 3/2 * s ^(1/2)
2007-02-05 20:32:26 · answer #3 · answered by rawfulcopter adfl;kasdjfl;kasdjf 3 · 0⤊ 0⤋
multiply the exponent of s by s itself and subtract one from the exponent of s, and the constant i.e. 1, goes to zero
the answer is
dr/ds = 3/2s^1/2
2007-02-05 20:36:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
dr/ds = 3/2s^1/2
2007-02-05 20:31:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(3/2)s^(1/2)
2007-02-05 20:31:22 · answer #6 · answered by Professor Maddie 4 · 0⤊ 0⤋