How many moles of sulfate ions, cobalt(III) ions, and oxygen atoms are present in 0.408 mol of cobalt(III) sulfate?
I know how to do it but I just don't know the formula for cobalt(III) sulfate!
2007-02-05 12:21:59 · 7 answers · asked by beachbum 2 in Science & Mathematics ➔ Chemistry
Cobalt (III) is Co(3+)
Sulfate is SO4 (2-).
So the formula will be Co2(SO4)3.
2007-02-05 12:25:28 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
(Co+3)2 charge (SO4)3-2 charge
this 2 being 2 cobalt atoms. that 3 outside of the parentheses being two sulfate molecules. Good Luck!
2007-02-05 12:25:42 · answer #2 · answered by Donovan G 5 · 0⤊ 0⤋
The formula for cobolt III sulfate is:
Co2 (SO4)3
2007-02-05 12:27:01 · answer #3 · answered by sciencewiz 4 · 0⤊ 0⤋
Co2(SO4)3
2007-02-05 12:24:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Co2(SO4)3 Good luck with the rest!
2007-02-05 12:25:09 · answer #5 · answered by steve_geo1 7 · 0⤊ 0⤋
cobalt(iii) sulfate is...Co2(SO4)3
2007-02-05 12:27:07 · answer #6 · answered by jw361706 2 · 0⤊ 0⤋
co3- for cobalt
2007-02-05 12:24:52 · answer #7 · answered by ursoolastsumer 2 · 0⤊ 0⤋