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(m^4)^3 (m^2)^9
---------------------
(m^3)^2


and

How do I find the poynomial x^3 -4x when x = -2


Thanks :)

2007-02-05 12:19:56 · 2 answers · asked by CookFrNW 3 in Science & Mathematics Mathematics

2 answers

(m^4)^3 (m^2)^9 m^12 (m^18) m^30 m^24
--------------------- = ------------------- = --------- =
(m^3)^2 m^6 m^6


x^3 - 4x
(-2)^3 - 4(-2) = -8 +8 = 0

2007-02-05 14:14:16 · answer #1 · answered by MATHMANRET 2 · 0 0

first one: (m^4)^3(M^2)^9=(m^12)(m^18)=m^30
second one: (m^3)^2=m^6

2007-02-05 20:36:28 · answer #2 · answered by alirezamortezai 2 · 0 0

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