What is the inverse tangent of 0?

Question

The answer please in radians and degrees... I have 90 degrees and pie over 2...

Answer 1

0 and 0

Answer 2

No, pi/2 is a discontiuity of tangent, not a zero. Think about the identity tanx = sinx/cosx...

If you want arctan(0) (arctan is what we used to call the "inverse tangent" and for this medium is the more useful notation) look at the graph of tangent and find the places where y = 0. The one in tangent's first period is the one you're after.

You'll figure out from the picture that arctan(0) = 0.

Answer 3

When I put tan^-1 in the calculator, it gave me 0 for the answer. When I put cos^-1 in the calculator, it gave pi/2 in radians and 90 degrees in degree mode. I hope this helps!

Answer 4

The answer is 0. In both radians and degrees. ;-)

Note that tan x = sin x / cos x; sin 0 = 0, cos 0 = 1, so tan 0 = 0.

Answer 5

TAN(x) is 0 when x = 0 or π. Or more generally: 0, π, 2π, 3π, etc.

So the inverse tangent of 0 is nπ where n is an integer. In degrees this would just be 180n where n is any integer.

Answer 6

tan(0) = 0 whether degrees or radians

arctan(0) = 0 + kπ, where k is an integer (radians)
arctan(0) = 0 + 180k°, where k is an integer (degrees)

Answer 7

dude!!! it's Zero!