How many moles of carbonate ions, aluminum ions, and oxygen atoms are present in 29.0 g aluminum carbonate?
I really want to know how to do this! Don't just give me the answer!
2007-02-05 12:01:51 · 2 answers · asked by beachbum 2 in Science & Mathematics ➔ Chemistry
First thing to do is write the formula: Al forms a 3+ ion, and the carbonate ion is 2-, so the formula will be
Al2(CO3)3
The next step is to find the molar mass: we have two aluminium atoms at 27.0 each, 3 C atoms at 12.0 each and 9 O atoms at 16.0 each for a total of (2*27.0 + 3*12.0 + 9*16.0) = 234.0 g/mol.
So the number of moles of aluminium carbonate is 29.0 / 234.0 = 0.1239 mol.
From the formula, each mole of aluminium carbonate contains 3 mol of carbonate ions, 2 mol of aluminium ions, and 9 mol of oxygen atoms. So we have
(3 * 0.1239) = 0.372 mol of carbonate ions
(2 * 0.1239) = 0.248 mol of aluminium ions
(9 * 0.1239) = 1.12 mol of oxygen atoms.
2007-02-05 12:10:26 · answer #1 · answered by Scarlet Manuka 7 · 1⤊ 0⤋
Scarlet has it right :)
2007-02-05 12:14:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋