3x^2+39x+108=0?

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this is in chapter 10 section 7 how do u do it using ax^2+bx+c

2007-02-05 11:55:28 · 3 answers · asked by Shante R 1 in Science & Mathematics ➔ Mathematics

like this using ax^2+bx+c
can u explain it n a betta way cause your choices are -4 and -9 or -4 and 9 or -4 and 9 or 4 and 9

2007-02-05 12:12:58 · update #1

3 answers

It factors into (3x+12)(x+9)=0

So x=-4 and x=-9

2007-02-05 11:58:33 · answer #1 · answered by Chris S 3 · 0⤊ 0⤋

a = 3, b = 39, and c = 108
I would solve
3x^2 + 39x + 108 = 0
as follows: First divide everything by 3:
x^2 + 13x + 36 = 0
Then factor:
(x + 4)(x + 9) = 0
x = -9, -4

2007-02-05 12:05:53 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋

3(x+4)(x+9) = 0
x = -4 or x = -9

2007-02-05 12:01:55 · answer #3 · answered by koolkat 3 · 0⤊ 0⤋