A tank of water has a base a circle of radius 2 meters and vertical sides. If water leaves the tank at a rate 2 liters per minute, how fast is the water level falling in centimeters per hour? [1 liter is 1000 cubic centimeters]
2007-02-05 11:51:13 · 4 answers · asked by crzylaker 2 in Science & Mathematics ➔ Mathematics
2L/min = 120 L/hr = 120,000 cc/hr
base of tank = pi r^2 = 2e4 pi sq cm
120000 cc/hr / 2e4 pi sq cm = 3/pi = 0.955 cm/hr
2007-02-05 11:57:51 · answer #1 · answered by feanor 7 · 0⤊ 0⤋
2 m = 200 cm
Base Area = Ïr^2 = Ï(200)^2 = 40,000Ï cm^2
dv/dt = -2000 cm^3 per minute = -120,000 cm^3 per hour
-120,000 / (40,00Ï) = -3/Ï cm / hour = .955 cm / hour
2007-02-05 19:59:51 · answer #2 · answered by mrfahrenbacher 3 · 0⤊ 0⤋
Doesn't require calculus.
Algebra is enough.
2007-02-05 19:54:23 · answer #3 · answered by Old F 1 · 0⤊ 1⤋
do your own homework, einstien
2007-02-05 19:54:24 · answer #4 · answered by bubbles 3 · 0⤊ 1⤋