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assuming no air resistance, how long does it take a penny to fall if it was dropped from the CN Tower (553 m)? accerleration due to gravity is 9.;8 m/s^2...

what i got...Givn: t=? d=553 m a=9.8m/s^2 v1=0
the equation should be...d=v1t+1/2at^2 rite?...and all i have to do is to move t by it self?...thats where i get stuck...

2007-02-05 11:43:22 · 1 answers · asked by no name 1 in Science & Mathematics Physics

1 answers

d = v1 t + 1/2 a t^2
=> 553 = 0 t + 1/2 (9.8) t^2
=> 4.9 t^2 = 553
=> t^2 = 113
=> t = √113 = 11 sec.

2007-02-05 11:47:59 · answer #1 · answered by Scarlet Manuka 7 · 0 0

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