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I need help solving this. I really have trouble solving for a letter. Here is the problem. Thanks in advance.

s=2Lh+2Lw+2wh, solve for L.

2007-02-05 11:05:08 · 4 answers · asked by artistic_c 1 in Science & Mathematics Mathematics

4 answers

s = 2Lh + 2Lw + 2wh

First get everything without an L on one side:

s - 2wh = 2Lh + 2Lw

Now, factor out the L:

s - 2wh = L(2h + 2w)

Now divide both sides by the stuff next to the L:

(s - 2wh) / (2h + 2w) = L

2007-02-05 11:11:41 · answer #1 · answered by Mathematica 7 · 2 0

There's a couple ways. One is substitution- get the problem so that one variable is alone on one side. So you have s=50+2f. Then, since you know that s is the same as 50+2f substitute that back into the original equation. So instead of 4f+2s=100 you have 4f+2(50+2f)=100. Then once you figure out what f is, you can substitute that into the original equation and solve for s. Hope that helps!

2016-03-29 06:40:50 · answer #2 · answered by Anonymous · 0 0

s/2= Lh + Lw + wh
s/2 - wh = L (h +w)
[s/2 -wh]/ (h + w) = L


send word if you need more steps

2007-02-05 11:09:11 · answer #3 · answered by suggargurl302 2 · 0 0

2L(h+w) = s-2wh
L = (s-2wh)/2(h+w)

2007-02-05 11:09:38 · answer #4 · answered by kellenraid 6 · 0 0

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