A 6.0*10^2-g sample of of water at 90.0º Celsius is mixed with 4.00*10^2-g of water at 22.0º Celsius...?

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A 6.010^2-g sample of of water at 90.0º Celsius is mixed with 4.0010^2-g of water at 22.0º Celsius...?

A 6.0*10^2-g sample of of water at 90.0º Celsius is mixed with 4.00*10^2-g of water at 22.0º Celsius. Assume that there is no heat loss to the surroundings. What is the final temperature of the mixture?

This problem is giving me trouble.
Please help me.

2007-02-05 10:54:16 · 2 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics

2 answers

T=(m1+c1+T1+m2+c2+T2)/(m1*c1+m2*c2)
T=(.6kg+4180J/kgC+90C+.4kg+4180J/kgC+22C)/ (.6kg*4180J/kgC+.4kg*4180J/kgC)
=2.027
you're welcome
i deserve a star for that

2007-02-05 11:09:03 · answer #1 · answered by snake_hunter469 2 · 0⤊ 0⤋

Um you have Merill Physics: Princibles and Problems textbook also?

2007-02-05 11:30:46 · answer #2 · answered by roarius19 1 · 0⤊ 0⤋