English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A) slope = -1
B) slope= -2
C) slope= 1
D) slope= 0
E) slope= 2

2007-02-05 10:32:58 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

y = x^2 - 4x

To find the slope at (1, -3), we need to first find dy/dx, and then plug in the value x = 1.

dy/dx = 2x - 4

Therefore, for x = 1,

m = 2(1) - 4
m = 2 - 4
m = -2

2007-02-05 10:38:37 · answer #1 · answered by Puggy 7 · 0 0

Your function is extra advantageous written as (a million/2)e^x the factor of tangency is (Ln(3), 3/2) y' = (a million/2)e^x confident, that's the comparable function So the slope of the tangent line at (Ln(3), 3/2) is y = 3x/2 + 3/2(a million - Ln(3))

2016-12-17 03:14:09 · answer #2 · answered by ? 4 · 0 0

differentiate:

dy = (x^2 -4x)dx
= 2x-4
set equal to zero and evaluate at x=1
0=2 - 4 = -2
the required slope is -2

2007-02-05 10:42:31 · answer #3 · answered by bignose68 4 · 0 0

Slope = dy/dx = 2x - 4 = 2 . 1 - 4 = - 2

Ans: B

2007-02-05 10:40:22 · answer #4 · answered by Sheen 4 · 0 0

DO YOU ROWN HOMEWORK!

2007-02-05 10:40:20 · answer #5 · answered by Anonymous · 0 1

fedest.com, questions and answers