2007-02-05 09:51:59 · 10 answers · asked by alona p 1 in Science & Mathematics ➔ Mathematics
3/2 + sqrt(2)
2007-02-05 09:59:46 · answer #1 · answered by DriverRob 4 · 0⤊ 0⤋
Square Root Of 2 4
2016-11-04 06:00:51 · answer #2 · answered by leesa 4 · 0⤊ 0⤋
6 / [4 + sqrt(2)]
The rule is, we *never* want a radical on the bottom.
To get rid of this, we need to multiply top and bottom by the conjugate of the denominator.
The conjugate of 4 + sqrt(2) is 4 - sqrt(2), and remember that multiplying (a + b) by a conjugate (a - b) will yield a difference of squares, a^2 - b^2. Therefore we will have
6[4 - sqrt(2)] / [4^2 - [sqrt(2)]^2]
6[4 - sqrt(2)] / [16 - 2]
6[4 - sqrt(2)] / 14
Simplifying by noting the 6 and 14 have a common factor of 2,
3[4 - sqrt(2)] / 7
2007-02-05 09:55:49 · answer #3 · answered by Puggy 7 · 1⤊ 0⤋
6/4 + root 2
1 2/4 = 1 1/2 or 1.5
the square root of 2 = 1.414
so,
1.5 +1.414 = 2.914
2007-02-05 09:55:53 · answer #4 · answered by Sparky 4 · 0⤊ 1⤋
6/4=1.5 and the square root of 2 is 4 so 1.5 plus 4=5.5
2007-02-05 09:56:04 · answer #5 · answered by Anonymous · 0⤊ 1⤋
the square root of 2 is 1.414
6/4+1.414
=6/5.414
=1.1082379017362393793867750277079
2007-02-05 18:51:20 · answer #6 · answered by mitul goel 2 · 0⤊ 1⤋
6/4=1.5 square root of 2=1.41 --- 1.41+1.5=2.91 Simplified the answer would be 3
2007-02-05 09:54:59 · answer #7 · answered by hvandyk82 2 · 0⤊ 1⤋
depending on the parenthesis:
(-3(root2-4))/7
or
root2 + 3/2
2007-02-05 09:55:39 · answer #8 · answered by Michael D 2 · 0⤊ 1⤋
6 4 - sq rt 2 24-6 sq rt 2 ----------------------------------------... 4+ sq rt 2 4 - sq rt 2 14 12-6 sqrt 2 =========== 7 correct
2016-03-18 01:34:33 · answer #9 · answered by Anonymous · 0⤊ 0⤋
2.91421356
2007-02-05 09:55:03 · answer #10 · answered by highpriest12321 2 · 0⤊ 1⤋