What would be the quadrant for the following expression: -pi/2 less than x less than 0?
And also how would you find the exact value of sin 225 when you only know the angle which 225?
2007-02-05 08:39:44 · 2 answers · asked by venus 1 in Science & Mathematics ➔ Mathematics
what would be the quadrant for 0 less than x less than pi? Would that be II quadrant?
2007-02-05 09:45:04 · update #1
-pi/2 < x < 0
Okay. . .on the unit circle, where are -pi/2 and 0 located?
-pi/2 is located on the negative half of the y-axis, and 0 is located on the positive x-axis. Therefore, Fourth Quadrant (Quadrant IV).
2007-02-05 08:47:28 · answer #1 · answered by infinitys_7th 2 · 0⤊ 0⤋
the quadrant would be IV (four).
Sin = opp/hyp. Since the opp = -1 and the hyp = sqrt(2), the answer is -sqrt(2)/2.
2007-02-05 08:44:33 · answer #2 · answered by Dave 6 · 0⤊ 0⤋