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(sinxcosy+cosxsiny) / (cosxcosy-sinxsiny) = (tanx+tany) / (1-tanxtany)

i know you can only work on one side of the problem....but i really dont know how to do this one. i know its alot of work, so if you decide to give it a try thanks so much.

2007-02-05 08:28:10 · 1 answers · asked by Anonymous in Education & Reference Homework Help

1 answers

sinxcosy + cosxsiny = sin (x + y)

cosxcosy-sinxsiny = cos(x+y)

sin (x +y)/ cos (x + y) = tan( x + y), which is the equation you have on the right there.

TADA

2007-02-05 13:21:53 · answer #1 · answered by Ace 4 · 0 0

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