In a certain puzzle, the larger of two numbers must be five more than three times the smaller. The diffrence between the two numbers must be 31. Find the numbers
2007-02-05 08:12:46 · 3 answers · asked by ~*PrInCeSs*~ 2 in Science & Mathematics ➔ Mathematics
x = larger, y = smaller
x = 3y + 5
x - y = 31
substitue 3y + 5 for x into the second equation:
(3y + 5) - y = 31
2y + 5 = 31
2y = 26
y = 13
x - y = 31
x - 13 = 31
x = 44
Now let's check the first equation:
x = 3y + 5
44 = 3(13) + 5
44 = 39 + 5
44 = 44
Hope this helps! :)
2007-02-05 08:16:12 · answer #1 · answered by disposable_hero_too 6 · 1⤊ 0⤋
44 AND 39
2007-02-05 16:20:19 · answer #2 · answered by bartenderjackbartenderjack 1 · 0⤊ 0⤋
y = 3x +5
y - x = 31
y = x + 31
So:
3x + 5 = x + 31
2x = 26
x = 13
y = 44
2007-02-05 16:17:19 · answer #3 · answered by Robert M 2 · 0⤊ 0⤋