factoring trinomials
2007-02-05 08:08:48 · 7 answers · asked by brian k 1 in Science & Mathematics ➔ Mathematics
(2x+3)*(2x-1)=0
2x+3 = 0, x = -3/2
2x-1 = 0, x=1/2
2007-02-05 08:12:38 · answer #1 · answered by Anonymous · 1⤊ 0⤋
4x²+4x-3
You need to know the factor sets of the first and last term
(1,4) or (2,2)... the last term is (1,3) only.
The first term is positive, so both factors will be positive. The last term is negative, so one factor will be positive and the other negative.
Now you need to work these so that the middle term = +4x
(x-3)(4x+1)? no
(2x-3)(2x+1) the middle term is -6x + 2x or -4x. This means I'm on the right track, but need to reverse the - and + signs.
(2x+3)(2x-1) is the correct factorization.
2007-02-05 16:14:52 · answer #2 · answered by bequalming 5 · 1⤊ 0⤋
4x^2 + 4x - 3
Do trial and error. Notice that 4x^2 splits up into 2x and 2x.
(2x + ?)(2x + ?)
Now, try factors of -3. Try -3 and 1.
(2x - 3)(2x + 1)
The outside is equal to 2x, and the inside is equal to -6x. Added together, you get -4x; we want +4x. Due to this incorrect sign, all we have to do is switch the signs around.
Try 3 and -1.
(2x + 3)(2x - 1)
The outside is equal to -2x, and the inside is equal to 6x. Added together, we get 4x, which is what we want. Therefore, this is the correct factorization.
2007-02-05 16:12:46 · answer #3 · answered by Puggy 7 · 1⤊ 1⤋
oh Man ! I LOVE Factorising!!!!!
ok 4x^2 + 4x - 3
(2x - 1) ( 2x + 3)
Done
Have
A
Nice
Day
2007-02-05 16:14:16 · answer #4 · answered by Miss LaStrange 5 · 1⤊ 0⤋
4x² + 4x - 3
4x² - 2x + 6x - 3
2x(2x - 1) + 3(2x - 1)
(2x + 3)(2x - 1)
- - - - - - - - - - - - -s-
2007-02-05 16:25:49 · answer #5 · answered by SAMUEL D 7 · 1⤊ 0⤋
(2x-1)(2x+3)
2007-02-05 16:12:56 · answer #6 · answered by lauren_brooke19 1 · 1⤊ 0⤋
E=mc2. Figure it out , yourself.
2007-02-05 16:16:12 · answer #7 · answered by Anonymous · 1⤊ 0⤋