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2007-02-05 07:57:35 · 7 answers · asked by bigdaddy89 2 in Science & Mathematics Mathematics

7 answers

your question is wrong... 0 exponent 0 is not equal to 1...

2007-02-05 09:21:31 · answer #1 · answered by Anonymous · 0 0

No matter what number you have as the base, if the exponent is zero, then your answer is always 1. 10^0 = 1 5^0 = 1 87^0 = 1 etc. With negative exponents, just take the reciprocal of the whole number and make the base positive. -2^-4 = 1/(-2^4) = 0.625 5^-2 = 1/(5^2) = 0.04 Hope this helps!

2016-05-24 19:06:28 · answer #2 · answered by Anonymous · 0 0

Exponents one and zero
The meaning of 3^5 may be viewed as 1·3·3·3·3·3 : the starting value 1 (the identity element of multiplication) is multiplied by the base as many times as indicated by the exponent. With this definition in mind, it is easy to see how to generalize exponentiation to exponents one and zero: 3^1 = 1·3 = 3 and 3^0 = 1. This leads to the following rules:

Any number to the power 1 is itself.
Any nonzero number to the power 0 is 1; one interpretation of these powers is as empty products.

2007-02-05 08:01:31 · answer #3 · answered by MamaMia © 7 · 1 0

a^5 = a * a * a * a * a
a ^4 = a^5/a = a * a * a * a * a/a = a * a * a * a
a ^3 = a^4/a = a * a * a * a/a = a * a * a
a ^2 = a^3/a = a * a * a/a = a * a
a ^1 = a^2/a = a * a/a = a
a^0 = a^1/a = a/a = 1

2007-02-05 08:01:38 · answer #4 · answered by Tom :: Athier than Thou 6 · 1 0

Look at the law of exponents. N^x/N^y = N^(x-y). If x was equal to y it would be obvious that the fraction was equal to 1 and x-y would be 0.

2007-02-05 08:06:56 · answer #5 · answered by Barkley Hound 7 · 1 0

(X^A) * (X^B) = X ^ (A+B)

It's fairly obvious why that makes sense if A and B are positive integers.

Extending that to the case when A = 0, it is then obvious that X^0 has to equal 1.

2007-02-05 08:04:37 · answer #6 · answered by Curt Monash 7 · 1 0

n³ = n^4 / n
n² = n³ / n
n¹ = n² / n
n^0 = n¹ / n = n/n = 1.

Fore more info read:
http://en.wikipedia.org/wiki/Empty_product

2007-02-05 08:02:54 · answer #7 · answered by Anonymous · 0 0

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