2007-02-05 07:01:39 · 7 answers · asked by ld 1 in Science & Mathematics ➔ Chemistry
If 0.1 mole ethanol is dissolved in 100 cm3
Then in 10 x 100 = 1000cm3(1 dm3) then there is
10 x 0.1 = 1.0 moles in 1 dm3
Conc.n = 1.0 mol/dm3
2007-02-05 08:35:06 · answer #1 · answered by lenpol7 7 · 0⤊ 0⤋
If you are looking for moles per litre, there is an easy approximate answer and a harder one. The easy one is that 100 cm3 is 0.1 litre. So you've got .1 mole in .1 L, giving 1 mole/L.
However, the volume should be volume of solution, not volume of solvent (water). The approximate answer assumes that the volume doesn't change much when the ethanol is added. If you know the density of ethanol, you can calculate the volume of ethanol and add that to the water. That would bring the concentration slightly below 1 mole/L. But even that is not quite right, because the volume of the solution would be a little less than the volume of the ethanol plus the volume of the water. (Mass is conserved, but volume isn't.). That would bring the concentration back up a bit, but not all the way to 1 mole/L.
2007-02-05 07:10:43 · answer #2 · answered by Rob S 3 · 0⤊ 0⤋
I Molar = 1 mole dissolved in 1000 cm3 of water.0.1mole in 1000cm3 of water =0.1 molar.0.1 mole in 100 cm3 of water=1 Molar
2007-02-05 07:11:55 · answer #3 · answered by SAMMY 3 · 0⤊ 0⤋
Well, you have a concentration of water you can't drink and ethanol that won't even get you out of the driveway so that is one useless experiment.
2007-02-05 07:18:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
0.1 mole/100cc = 1 mole/L = 1 M
2007-02-05 07:07:28 · answer #5 · answered by Jabberwock 5 · 0⤊ 0⤋
molar mass ethanol= 46.07 g per mol
so there are 4.61 g in 0.1 mol ethanol
therefore:
ethanol concentration= 4.6% (v/v)
2007-02-05 08:32:15 · answer #6 · answered by BB 7 · 0⤊ 0⤋
n= VM/1000
M = 1000n/V = 1000*0.1/100 = 1M
2007-02-05 08:35:01 · answer #7 · answered by SS4 7 · 0⤊ 0⤋