2007-02-05 06:51:00 · 4 answers · asked by changchih 7 in Science & Mathematics ➔ Mathematics
what is a general formula for this sequence, 1, (1/4), (1/9), (1/16), (1/25)?
U_1 = 1 = 1/1 = 1/(1)²
U_2 = 1/4 = 1/(2)²
U_3 = 1/9 = 1/(3)²
U_4 = 1/4 = 1/(2)²
U_5 = 1/25 = 1/(5)²
So U_n = 1/n² where n is the ordinal number of the term. Thus the least value of n = 1 (there is no term before the 1st one or it would not be the first one)
2007-02-05 06:59:06 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
the sequence is 1/n^2 for all values of n except 0.
2007-02-05 14:58:53 · answer #2 · answered by bignose68 4 · 0⤊ 0⤋
int n, x
For n = 0 to infinity
do
x=n+1/(n+1)^2
n=n+1
2007-02-05 15:02:44 · answer #3 · answered by Jack Chedeville 6 · 0⤊ 0⤋
f(n)=1/n²
f(1) = 1/1² = 1
f(2) = 1/2² = 1/4
f(3) = 1/3² = 1/9
etc.
2007-02-05 14:56:30 · answer #4 · answered by Greg H 3 · 2⤊ 0⤋