2007-02-05 05:41:40 · 19 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The buoyancy force is 75-60 N, ie 15 N.
It means 15/10 (g=10) = 1.5 kg of water in weight is displaced by the metal. Since density of water is 1000kg/m^3, then volume of water displaced is 1.5/1000 m^3, which, according to Archimedes principle, is the volume of the object.
Density of object is now 7.5 kg (from 75 N) divided by volume.
D = (7.5/1.5)*1000 kg/m^3 = 5*10^3 kg/m^3, or 5 times the density of water.
2007-02-05 05:52:27 · answer #1 · answered by Sir Richard 5 · 0⤊ 0⤋
5 g/cc
The loss of 15 N while being under water means that 1/5 of its weight is taken over by buoyancy. Since water has a density of 1 g/cc, then the metal must have a density 5 times that of water.
2007-02-05 05:47:14 · answer #2 · answered by Vincent G 7 · 1⤊ 0⤋
Your metal displaces 1/5 its mass in water ((75-60)/75) so density is 5 times the density of water.
Best of luck - Mike
2007-02-05 05:49:21 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2017-03-11 00:25:02 · answer #4 · answered by ? 3 · 0⤊ 0⤋
Stand up each time you talk for the phone.
2017-03-06 02:19:50 · answer #5 · answered by ? 3 · 0⤊ 0⤋
Teach your kids your best sport (or have them educate you theirs).
2017-02-15 18:17:39 · answer #6 · answered by lorenzo 3 · 0⤊ 0⤋
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2016-06-25 18:24:48 · answer #7 · answered by ? 3 · 0⤊ 0⤋
its density is 5 t/m3 , here we are :
its weight in air = density*volume =75----eq1
In water = (density-1)*volume = 60 ---- eq2 . (due to upthrust force=volume*water density)
dividing eq1 & eq 2:
density*volume 75
{ ------------------------- = ----- }
(density-1)*volume 60
75*density-75=60*density
15*density=75
so density = 5 S.I units
2007-02-05 05:57:19 · answer #8 · answered by most 1 · 0⤊ 0⤋
I think by density u mean the Relative Density (R.D.), i.e., density of substance relative to density of water. There is a simple formula for calculating the RD of any solid by such observations...
Wt. of solid in air
--------------------------------------------------
Wt. of solid in air - Wt. of solid in water
=> Wt. of solid in air
-----------------------------------
Loss of wt. of solid in water
By ur observations - RD = 75/(75-60)
= 75/15
= 5.
Therefore, density of metal = 5 gcm^-3
2007-02-05 06:18:03 · answer #9 · answered by AeroAndy 2 · 0⤊ 0⤋
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2016-04-21 14:41:53 · answer #10 · answered by ? 3 · 0⤊ 0⤋