need calculus help badly?

Question

#1 Assume that f ''(x) is continuous on the closed interval [0,5], that f(0)=2, f(5)=7, and f'(5)=3. Then integral (0 to 5) x*f ''(x)*dx =

Answer 1

Integrate by parts
= xf´(x)(betw een0 and 5 -Integral (0,5 ) f´(x) But the integral of f´(x) is f(x)

So it becomes x*f´(x)-f(x) taken between (0,5) = 5*3-7+2=10

Answer 2

well try to do this:

int(0 to 5) x*f''(x)*dx = int(0 to 5) x*d(f'x) = x*f'(x) (0 to 5) - int (0 to 5) f'(x)*dx = x*f'(x) (0 to 5) - f(x) (0 to 5)

and then just calculate the values.. but you'll need f'(0) too. :)