how do i simplify A=½d1d2 in terms of d1?
how do i simplify A=½h(b1+b2) in terms of b1, b2, and h?
how do i simplify A=(pi)ab in terms of a and in terms of b?
2007-02-05 04:35:46 · 3 answers · asked by Leonard 1 in Science & Mathematics ➔ Mathematics
a = 1/2 D1 D2
2 * a = 2 * 1/2 *D1 * D2
2a = D1 * D2
2a / D2 = D1 * D2 / D2 = D1 * (1 ) = D1
D1 = 2a / D2
It's called solving for a variable not simplifying.
use the same method for the others.
keep working problems until you can do it in your head
B1 = 2a/h - B2
B2 = 2a/h - B1
h = 2a /(B1+B2)
a = A/pi /b = A / (b * pi)
b = A/pi /b
2007-02-05 04:42:11 · answer #1 · answered by Grant d 4 · 0⤊ 0⤋
Simplification is a process where you display a Algebraic equation in it's simplest form. For instance 2x+3x becomes 5x on simplification
I think you may want to re-arrange the equation (s) to make each term(s) the subject, if this is the case, looking at the first we have:
A=1/2d1d2 multiplying by 2 we get :
2A=d1d2 Dividing by d2 we get:
2A/d1=d1
This is an equation with 'd1' as the subject in 'terms'of A and d1.
I hope this is what you mean, regards Leigh
2007-02-05 12:58:58 · answer #2 · answered by leigh w 1 · 0⤊ 0⤋
A=½d1D2
2A=d1D2
2A=2dD
A=dD
2007-02-05 12:41:20 · answer #3 · answered by green_maths_scout 2 · 0⤊ 1⤋