algebra question?

5 ⤊

41 less than or equal to 7 /x + 9/ -8

2007-02-05 04:04:22 · 5 answers · asked by dan b 1 in Science & Mathematics ➔ Mathematics

Dan, you need to do your own homework, really, I can answer your question but it won't teach you anything...think for yourself.

2007-02-05 04:07:43 · answer #1 · answered by Anonymous · 5⤊ 1⤋

7/x >= 41+9/8

x <= 7/(41+9/8)

2007-02-05 12:09:58 · answer #2 · answered by gebobs 6 · 0⤊ 0⤋

41 <= 7|x + 9| - 8
49 <= 7|x+9|
|x + 9| >= 7

x >= -2 or x <= -16

2007-02-05 12:09:33 · answer #3 · answered by Dave 6 · 0⤊ 0⤋

41 <= 7/x + 9/-8
41 - 9/-8 <= 7/x
41 + 9/8 <= 7/x
(41 9/8) * x <= 7
x <= 7/(41 9/8)
x <= 7/42.125
x <= 0.16617 (approx.)

2007-02-05 12:07:06 · answer #4 · answered by Steven D 5 · 0⤊ 0⤋

yes

2007-02-05 12:07:01 · answer #5 · answered by juanramoz2 3 · 0⤊ 1⤋