about three or your years ago the kings had a chance to win the championships when they played the lakers. I guess my question is does anyone think the kings will ever be as good as they used to be?
2007-02-05 02:17:42 · 7 answers · asked by Anonymous in Sports ➔ Basketball
If they do, it won't be very soon. Bibby is struggling and on the verge of his lowest season shooting percentage in his career. If you saw the Sacramento Bee this morning, they are thinking of trading him. If they are having this much trouble with there point guard, who runs the offense, they are in some serious trouble (Ron Artest can't do everything!!!). Musselman isn't helping things, I mean he's suspended for DUI (ISN'T THAT ENOUGH?!?!?) and since then, we've won 3 straight games with our ASSISTANT COACH!!!
2007-02-07 12:08:22 · answer #1 · answered by Wildcat 2 · 0⤊ 0⤋
No the Kings had a small window of opportunity to win a championship - that window has been shut and locked. There's way too many talented teams in the West for the Kings to compete with.
2007-02-05 15:47:48 · answer #2 · answered by RichMac82 6 · 0⤊ 0⤋
Well, a couple of years ago, the New Orleans saints in the NFL were terrible, and now, they are one of the top 2 teams in the NFC. While the only great players they have now are Bibby and Martin, they will get better players eventually, so, yes, they will win, although it may take a while.
2007-02-05 10:23:37 · answer #3 · answered by yahskaraghu 4 · 0⤊ 0⤋
this is gonna sound like its coming from a cali surfer or sum **** but i think they will jus because there team is in cali and players these days wanna go to sweet states thats hott and hott gurls(no lie) so yeah i do think so in the future
2007-02-05 10:56:58 · answer #4 · answered by Detroitsports4lyfe 2 · 0⤊ 0⤋
yeah someday not anytime soon though
2007-02-05 10:22:31 · answer #5 · answered by Q_RICH23 2 · 0⤊ 0⤋
i don't think that, no good players
2007-02-05 11:28:19 · answer #6 · answered by Pistonsfan101 5 · 0⤊ 0⤋
sorry nope
2007-02-05 10:32:38 · answer #7 · answered by paul lee 2 · 0⤊ 0⤋