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In a television set, electrons are accelerated from rest through a potential difference of 17 kV. The electrons then pass through a 0.29 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.

2007-02-05 01:14:47 · 3 answers · asked by Hey Carl 1 in Science & Mathematics Physics

the charge of an elctron is (-1.6 x 10^-19)

I think the formula is F= qvB

I am not sure how to find V the velocity

Is this right?

2007-02-05 02:18:14 · update #1

3 answers

It's a vector operation involving the cross product. The mag field tends to make the electron curve.

The force is qV X B where q is the amount of charge, V is the velocity vector and B is the vector of the magnetic B field. Of course, you need to calculate the velocity due to an electron picking up 17keV of energy in the E field.

2007-02-05 02:13:24 · answer #1 · answered by Gene 7 · 0 0

The question would not state the direction of the particle relative to the field. Assuming it rather is intentional: a million. is often really. yet even as the teachings of the cost and field are parallel, there is 0 rigidity. so that you'll might want to make sure for your self if this should be referred to as really or fake! 2 it rather is often fake. If there's a rigidity, it rather is often perpendicular to both speed and field. 3 it rather is often really subsequently of actuality no paintings is done with assistance from using the field; so the particle's speed isn't replaced. the approach momentum ought to change yet now no longer the cost. 4. it rather is often fake for the rationalization defined in 3. 5. it rather is often fake for the rationalization defined in 2.

2016-11-02 09:20:52 · answer #2 · answered by Anonymous · 0 0

That's a difficult one, at least it is for me. I'm waiting to see the right answer.

2007-02-05 01:30:34 · answer #3 · answered by Joy K 4 · 0 0

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