...What are the chances of it happening 6 times out of 10 tries.
Thanks.
2007-02-04 22:48:36 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Ok.
Chance= 60/100.
Probability of success (say 'p') = 0.6
Probability of failure (say 'q') = 1-0.6 = 0.4
Going by binomial distribution with parameters 'n' and 'p'..consider 10 bernoulli trials.
Let x be the number of success ie the chances of the event happening in 10 trials
now, n = 10, p = 0.6
The formula goes as:
Probability that (x = 6) = [ nCx ]*[(p)^x ]*[(q)^(n-x)]
nCx= number of times x is selected out of n cases... I sure hope you know how permutations and combinations work!
Going by the formula,
Probability that (x = 6) = [n!/ x!(n-x)!] * [p^x] * [q^(n-x)]
= 10!/(6!* 4!) * (0.6)^6 * (0.4)^4
= 0.250822656
That's your answer! Hope I helped...
2007-02-04 23:16:59 · answer #1 · answered by Smarty 2 · 0⤊ 0⤋
60 %
2007-02-05 07:04:32 · answer #2 · answered by Saloni 2 · 0⤊ 1⤋
Look up the "binomial distribution"
2007-02-05 06:51:06 · answer #3 · answered by Curt Monash 7 · 0⤊ 0⤋
100%
2007-02-05 06:52:21 · answer #4 · answered by woi 2 · 0⤊ 2⤋