The polynomial f(x) divided x-3 results in a quotient of x^2+3x-5 with reaminder of 2. Find f(3)?

Answer 1

the answer is 2
multiply the quotient and the term (x-3)
then add the remailder(in this case=2)
the polynomial f(x)=x^3-14x+17
put x=3 in the function
and u get 2
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alternatively
x-3 divides the polynomial with remainder=2
in remainder and factor theorem, we know thar if f(a)=0
then x-a is a factor
otherwise the remainder is the value of f(a)

Answer 2

F(3)=2
because F(x)=(x-3)(x^2+3x-5)+2
then asume x=3, then F(x)=2

Answer 3

f(3) = (3 - 3)(3^2 + 3*3 - 5) + 2
f(3) = 2