These are solutions and the answer is because of the different degrees of ionisation of the three compounds when dissolved in water. The greater the ionisation, the greater the conductivity.
2007-02-04 20:43:38
·
answer #1
·
answered by JJ 7
·
1⤊
0⤋
at first even even with the actuality that your question is valid, your imaginary planet, i ought to mission to say is rather a lot imaginary. close by concentrations of gases are common to exist notwithstanding, and the finished purple Spot on Jupiter is a first party. The implication out of your question is that each and every one greenhouse gas is CO2. this isn't authentic. there are countless different greenhouse gases CH4 is a first party. some greenhouse gases are more suitable than others which means that for an identical volume of gas the heating result's more effective. for the reason that more suitable greenhouse gases do exist, and also you've were given conditioned your question on the equality of the mass, a greenhouse gas it truly is more suitable than CO2 for an identical volume of molecules, will produce tremendous heating result if the ability of the different greenhouse gas is larger than the ratio of a mole of the wanted different greenhouse/ the mole of CO2, there's a heating result more effective than that produced with assistance from an identical mass of CO2, if the ratio of the respective moles exceeds the inverse. Given an identical mass of CO2 a gas with two times the molecular weight of CO2 ought to include one 1/2 as many molecules. The heating result to be more effective than that of CO2 ought to might want to be more effective than 2.
2016-11-02 09:01:54
·
answer #2
·
answered by Anonymous
·
0⤊
1⤋