need help...thanks?

Question

A company's cost in pesos of producing x units of a certain product is given by C(X) = 800 + 0.4x + 0.0002x^2 [<

Answer 1

average cost
y = 0.0002x + 0.4 + 800/x
0 = 0.0002 - 800/x^2
0.0002x^2 = 800
x^2 = 4,000,000
x = 2,000 units

Answer 2

Have you written this question correctly? Are you sure there isn't a minus in it instead of a plus. What you have is that the more of these the company makes, the higher the cost per item. Normally the cost decreases when you make more of them. There's definitely something wrong here.

As it stands, gimb1960 is right - the level of production that minimizes average cost per unit is zero - that is, the company should make nothing.

Answer 3

I'm almost sure this solution.

U(x)=C(x)/x=(4/(10^8))*x + 0.4+(800/x)
(here U(x) is the fn getting cost per unit)

U'(x)=4/(10^8) - (800*(x^2)) ..............................(Expr1)
U''(x)=1600/(x^3)>0 (x>0)

So the value x(when U'(x)=0) is the solution you want...

(Expr1).... U'(x)=4/(10^8) - (800*(x^2)) =0
x=1/( (sqrt(2)) * (10^5) )

here 1>x>0
Considering x is the n of production, the solution is x=1

{1}

If you have a problem on this solution...
please contact with me... ([e-mail])

Answer 4

i gues that it is where the minimum of the parabola is
am i right ? so (sqrt(0.0002)x + 0.4/ssqrt(0.0002))^2 - 0.4/ssqrt(0.0002) + 800

so 0 = sqrt(0.0002)x + 0.4/ssqrt(0.0002) or
x = - 0.4/0.0002

but this is negative so x = 0 is the best, ( local minimum )