x+a/x-a - (x+a)(x+a)/a(x-a)
x+a and (x+a)(x+a) are two numerators.
2007-02-04 19:05:17 · 4 answers · asked by lirael1019 1 in Science & Mathematics ➔ Mathematics
mult both numerator and denomiator of the first fraction by a to make the denominators the same. then it's easy.
a(x+a)-(x+a)(x+a)
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a(x-a)
get rid of the parenthesis in the numerator:
ax+a^2 - x^2 - 2ax - a^2
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a(x-a)
combine like terms
-ax - x^2
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a(x-a)
For all purposes, its done now...if you really want to be anal about it, you could factor the numerator if you want to...
-x(x+a)
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a(x-a)
I suppose it's a little "prettier"...
2007-02-04 19:21:30 · answer #1 · answered by sarajschryver 2 · 0⤊ 0⤋
I think it should be x^2 + ax
2007-02-05 03:34:36 · answer #2 · answered by jessica_1151 1 · 0⤊ 0⤋
(x + a)/(x-a) - (x + a)(x + a)/a(x - a) =
(a(x + a) - (x + a)(x + a))/a(x - a) =
((a - (x + a))(x + a)/a(x - a) =
(a - x - a)(x + a)/a(x - a) =
- x(x + a)/a(x - a)
2007-02-05 03:36:37 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
(x+a)/(x-a)-(x+a)^2/a(x-a)=
=(x+a)/(x-a)(1-(x+a)/a)=
=(x+a)/(x-a)(1-(x/a+1))=
=-(x+a)/(x-a)x/a=
=-x(x+a)/a(x-a)=
=-x/a(1+2a/(x-a))=
=-(x/a+2x/(x-a))=
=-(x/a+2+2a/(x-a))
2007-02-05 03:31:57 · answer #4 · answered by happyrabbit 2 · 0⤊ 0⤋