English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

3 answers

Depends on your available power. A simple circuit would involve an emitter follower, with the base driven by a Zener diode of appropriate voltage. But 3.6 volts is three NiCd cells, so if you can use batteries at all, that would be a simple way to do it.

2007-02-04 18:10:38 · answer #1 · answered by Anonymous · 1 0

nicely, that relies upon on the way you verify out it. The voltage for the duration of a battery is set by employing the electrochemical skill of the anode and cathode. In a feeling, this makes the battery a regulated resource of potential. while the capability in a battery is depleted, or present day draw exceeds the associated fee at which ions might nicely be transported around the electrolyte, the voltage drops, yet any regulated potential grant will stoop under heavy present day draw.

2016-12-17 09:37:16 · answer #2 · answered by ? 4 · 0 0

Do you wish to derive the power from line voltage? This is possible, but not a good idea because you would not be isolated.
rhsaunders is correct, with the addition of a bridge rectifier, filter capacitor and surge resistor.

2007-02-08 18:51:05 · answer #3 · answered by charley128 5 · 0 0

fedest.com, questions and answers