the largest diamond ever found was 621 g. if the force of gravitaional attraction between the diamond and a person witha mass of 65.0 kg is 1.00 * 10^-12 N, what is the distance between them?
keep gettin the wrong answer, i get like .16 ???
2007-02-04 16:53:59 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Fg = Gm1m2 / r^2
1x10^-12N = ((6.67x10^-11) (.621kg) (65kg)) / r^2
i got 51.89m. Maybe you should check your calculation again.
2007-02-04 17:02:04 · answer #1 · answered by 7 · 0⤊ 0⤋
F = G m1 m2 / r^2
=> 1.00x10^-12 = (6.67x10^-11) (0.621) (65.0) / r^2
=> r^2 = 2.692x10^-9 / 1.00x10^-12
=> r = √(2.692x10^3)
= 51.9 m.
It looks like somewhere you are out by a factor of 10^5. If you divided by 10^8 instead of 10^3 in converting g to kg, or if you had G = 6.67x10^-16 instead of 6.67x10^-11, you would get an answer of 0.164 m.
2007-02-04 17:04:18 · answer #2 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
Too small to degree. The tension in newtons could be F = g m1 m2/r^2, the place m1 = m2 = 12.5E9kg, r = 1E6 meters, and g, the difficulty-free gravitational consistent is 6.67E-11. You do the mathematics.
2016-09-28 10:46:58 · answer #3 · answered by barksdale 4 · 0⤊ 0⤋