When an electron is accelerated through a particular potential field, it attains a speed of 3.60 106 m/s....?

Question

When an electron is accelerated through a particular potential field, it attains a speed of 3.60 106 m/s. What is the characteristic wavelength of this electron?

Answer 1

What you're looking for is the de Broglie wavelength of a particle:
de Broglie Wavelength = h / p

h = Planck's Constant = 6.626 * 10 ^-34 kg m^2/s
p = mass of electron * velocity = 9.109 * 10^–31 kg * 3.60 * 10^6 m/s

λ = 6.626 * 10 ^-34 kg m^2/s / (9.109 * 10^–31 kg * 3.60 * 10^6 m/s)
λ = 2.02059 * 10^-10 m (solution!)